Answer :

The equation of the given circle is x^{2} + y^{2} – 4x – 8y – 45 = 0.

x^{2} + y^{2} – 4x – 8y – 45 = 0

(x^{2} – 4x) + (y^{2} -8y) =45

+ – 4 – 16 = 45

(x - 2)^{2} + (y – 4)^{2} =65

(x - 2)^{2} + (y – 4)^{2} =, which is form (x-h)^{2} +(y-k)^{2} = r^{2}, where h=2,

K= 4 and r=

Thus, the centre of the given circle is (2, 4), while its radius is.

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